WebNov 26, 2024 · pH p H of saturated solution of Ba(OH)2 B a ( O H) 2 is 12 12. The value of solubility product (K sp) ( K s p) of Ba(OH)2 B a ( O H) 2 is class-11 equilibrium 1 Answer 0 votes answered Nov 26, 2024 by Arnika Singh (73.7k points) selected Nov 26, 2024 by AasaSinha Best answer pH of solution = 12, [H +] = 10−12M = 12, [ H +] = 10 - 12 M WebpH of the saturated solution of Ba(OH)2 is 12. The value of solubility product (Ksp of Ba(OH)2 ) A 4.0×10−6 B 5.0×10−6 C 3.3×10−7 D 5.0×10−7 Hard Open in App Solution Verified by Toppr Correct option is D) Solve any question of Equilibriumwith:- Patterns of problems Was this answer helpful? 0 0 Similar questions
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WebThe concentration of an acid solution can be determined by titration with a strong base. First, calculate the number of moles of strong base required to reach the equivalence point of the titration. Then, using the mole ratio from the balanced neutralization equation, convert from moles of strong base to moles of acid. WebpH of a saturated solution of Ba (OH) 2 is 12. The value of solubility product K sp of Ba (OH) 2 is 3.3 x 10 -7 5.0 x 10 -7 4.0 x 10 -6 4.0 x 10 -6 B. 5.0 x 10 -7 Given, pH of Ba (OH) 2 = 12 … share price of us stocks 55
`pH` of saturated solution of `Ba(OH)_(2)` is `12`. The …
WebJun 25, 2024 · Now to find leftover moles, you’ll have to subtract as such ${1.53} \times 10^{-3} - 1.2 \times 10^{-3} = 3.3 \times 10^{-4}$, this is the excess moles of $\ce{Ba(OH)2}$. Looking at solution of excess $\ce{Ba(OH)2}$ $\ce{Ba(OH)2 -> Ba^2+ + 2 OH-}$ WebA 1. 4 5 8 g of Mg reacts with 8 0. 0 ml of a H C l solution whose pH is − 0. 4 7 7. The change is pH when all M g has reacted will be: Assume constant volume. WebAt 25 C, a 0.10% aqueous solution of adipic acid, C5H9O2COOH, has a pH of 3.2. A saturated solution of the acid, which contains 1.44 g acid per 100. mL of solution, has a pH = 2.7. Calculate the percent dissociation of adipic acid in each solution. share price of us stocks 530